What are the solutions to the equation x^2+4x+4=25 ?

The solutions to the equation x^2+4x+4=25 are x=3,x=-7

Find the zeros of x^2+4x+4=25

The zeros of x^2+4x+4=25 are x=3,x=-7

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x^{2} + 4 x + 4 = 25

x = 3, x = - 7

Solution steps

x^{2} + 4 x + 4 = 25

Move

25

to the left side

x^{2} + 4 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 21) = 10

x_{1, 2} = \frac{- 4 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 10}{2 \cdot 1}, x_{2} = \frac{- 4 - 10}{2 \cdot 1}

x = \frac{- 4 + 10}{2 \cdot 1} : 3

x = \frac{- 4 - 10}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 3, x = - 7

(1 + 3 i)^{2}

2 + n = 16

- 2 v = - 26

20 x^{2} + 12000 x + 72000 = 0

x^{4} + 2 x^{3}

What are the solutions to the equation x^2+4x+4=25 ?
The solutions to the equation x^2+4x+4=25 are x=3,x=-7
Find the zeros of x^2+4x+4=25
The zeros of x^2+4x+4=25 are x=3,x=-7