What is (4-3i)+(2i-8) ?

The solution to (4-3i)+(2i-8) is -4-i

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simplify (4-3i)+(2i-8)

simplify

(4 - 3 i) + (2 i - 8)

- 4 - i

Solution steps

(4 - 3 i) + (2 i - 8)

Rewrite

2 i - 8

in standard complex form:

- 8 + 2 i

= 4 - 3 i + - 8 + 2 i

Group the real part and the imaginary part of the complex number

(a + bi) + (c + d i) = (a + c) + (b + d) i

= (4 - 8) + (- 3 + 2) i

Simplify

(4 - 8) + (- 3 + 2) i : - 4 - i

= - 4 - i

- 2 (x + 1) < 2

32 t^{2} - 18 u^{2}

- 2 (4 y - 7) + y \geq 2 y - (- 5 + y)

56 \cdot 9 \div 14 \cdot \frac{1}{3}

x^{2} \geq x