What are the solutions to the equation x^2-5x-6=18 ?

The solutions to the equation x^2-5x-6=18 are x=8,x=-3

Find the zeros of x^2-5x-6=18

The zeros of x^2-5x-6=18 are x=8,x=-3

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x^{2} - 5 x - 6 = 18

x = 8, x = - 3

Solution steps

x^{2} - 5 x - 6 = 18

Move

18

to the left side

x^{2} - 5 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 24) = 11

x_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 1}

x = \frac{- ( - 5 ) + 11}{2 \cdot 1} : 8

x = \frac{- ( - 5 ) - 11}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 8, x = - 3

14 = \frac{1}{3} x + 5

x^{2} - 6 x - 12 = 0

2 x^{2} - x = 28

- 16 t^{2} + 47.2 t + 3 = 0

k^{2} + 2 k = 3

What are the solutions to the equation x^2-5x-6=18 ?
The solutions to the equation x^2-5x-6=18 are x=8,x=-3
Find the zeros of x^2-5x-6=18
The zeros of x^2-5x-6=18 are x=8,x=-3