What are the solutions to the equation 0=-16t^2+108t+520 ?

The solutions to the equation 0=-16t^2+108t+520 are t=-13/4 ,t=10

Find the zeros of 0=-16t^2+108t+520

The zeros of 0=-16t^2+108t+520 are t=-13/4 ,t=10

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0 = - 16 t^{2} + 108 t + 520

t = - \frac{13}{4}, t = 10

Decimal Notation

t = - 3.25, t = 10

Solution steps

0 = - 16 t^{2} + 108 t + 520

Switch sides

- 16 t^{2} + 108 t + 520 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 108 \pm 10 8 ^{2} - 4 ( - 16 ) \cdot 520}{2 ( - 16 )}

10 8^{2} - 4 (- 16) \cdot 520 = 212

t_{1, 2} = \frac{- 108 \pm 212}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 108 + 212}{2 ( - 16 )}, t_{2} = \frac{- 108 - 212}{2 ( - 16 )}

t = \frac{- 108 + 212}{2 ( - 16 )} : - \frac{13}{4}

t = \frac{- 108 - 212}{2 ( - 16 )} : 10

The solutions to the quadratic equation are:

t = - \frac{13}{4}, t = 10

\frac{5}{4 i}

\frac{2}{15} + \frac{5}{9}

25 rs + 25 r - 19 s - 19

x^{2} + 0.3 x - 0.1 = 0

(2 - 4 i)^{3}

What are the solutions to the equation 0=-16t^2+108t+520 ?
The solutions to the equation 0=-16t^2+108t+520 are t=-13/4 ,t=10
Find the zeros of 0=-16t^2+108t+520
The zeros of 0=-16t^2+108t+520 are t=-13/4 ,t=10