What is the answer to (3x+6)/2-(7x-14)/3-(x+1)/9 =0 ?

The answer to (3x+6)/2-(7x-14)/3-(x+1)/9 =0 is x=8

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(3x+6)/2-(7x-14)/3-(x+1)/9 =0

\frac{3 x + 6}{2} - \frac{7 x - 14}{3} - \frac{x + 1}{9} = 0

x = 8

Solution steps

\frac{3 x + 6}{2} - \frac{7 x - 14}{3} - \frac{x + 1}{9} = 0

Multiply by LCM

9 (3 x + 6) - 6 (7 x - 14) - 2 (x + 1) = 0

Expand

9 (3 x + 6) - 6 (7 x - 14) - 2 (x + 1) : - 17 x + 136

- 17 x + 136 = 0

Move

136

to the right side

- 17 x = - 136

Divide both sides by

- 17

x = 8

3 z^{3} + 2 z - 12 z^{2} - 8

2 c^{2} - 32 d^{2}

x^{2} - x - 2 > 0

\frac{1}{2} x^{2} - x - \frac{3}{2} = 0

8 x - 7 = - 5 x + 19

What is the answer to (3x+6)/2-(7x-14)/3-(x+1)/9 =0 ?
The answer to (3x+6)/2-(7x-14)/3-(x+1)/9 =0 is x=8
Solve for x: (3x+6)/2-(7x-14)/3-(x+1)/9 =0
The solution is x=8