What are the solutions to the equation 4x^2+x-33=0 ?

The solutions to the equation 4x^2+x-33=0 are x= 11/4 ,x=-3

Find the zeros of 4x^2+x-33=0

The zeros of 4x^2+x-33=0 are x= 11/4 ,x=-3

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4 x^{2} + x - 33 = 0

x = \frac{11}{4}, x = - 3

Solution steps

4 x^{2} + x - 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 ( - 33 )}{2 \cdot 4}

1^{2} - 4 \cdot 4 (- 33) = 23

x_{1, 2} = \frac{- 1 \pm 23}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 1 + 23}{2 \cdot 4}, x_{2} = \frac{- 1 - 23}{2 \cdot 4}

x = \frac{- 1 + 23}{2 \cdot 4} : \frac{11}{4}

x = \frac{- 1 - 23}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = \frac{11}{4}, x = - 3

\frac{2 - 4}{3 + 2}

(2 + a) - 3 (2 + a)^{2}

x - 2 x - 2 = 0

- x^{3} + 3 x^{2} + 9 x + 5

x^{2} = - 56 - 15 x

What are the solutions to the equation 4x^2+x-33=0 ?
The solutions to the equation 4x^2+x-33=0 are x= 11/4 ,x=-3
Find the zeros of 4x^2+x-33=0
The zeros of 4x^2+x-33=0 are x= 11/4 ,x=-3