What are the solutions to the equation (x+3)(x-1)=0 ?

The solutions to the equation (x+3)(x-1)=0 are x=-3,x=1

Find the zeros of (x+3)(x-1)=0

The zeros of (x+3)(x-1)=0 are x=-3,x=1

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(x + 3) (x - 1) = 0

x = - 3, x = 1

Solution steps

(x + 3) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x - 1 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 1 = 0 : x = 1

The solutions to the quadratic equation are:

x = - 3, x = 1

\frac{10}{80} \cdot \frac{72}{80}

256 x^{4} + 32 x^{2} + 1

2 x^{3} + 5 x - 8 x - 15

7 x^{2} - 5 x - 150

- x = 15

What are the solutions to the equation (x+3)(x-1)=0 ?
The solutions to the equation (x+3)(x-1)=0 are x=-3,x=1
Find the zeros of (x+3)(x-1)=0
The zeros of (x+3)(x-1)=0 are x=-3,x=1