What are the solutions to the equation 253692=29*12x*x ?

The solutions to the equation 253692=29*12x*x are x=27,x=-27

Find the zeros of 253692=29*12x*x

The zeros of 253692=29*12x*x are x=27,x=-27

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253692 = 29 \cdot 12 x \cdot x

x = 27, x = - 27

Solution steps

253692 = 29 \cdot 12 xx

Switch sides

29 \cdot 12 xx = 253692

Simplify

348 x^{2} = 253692

Divide both sides by

348

\frac{348 x ^{2}}{348} = \frac{253692}{348}

x^{2} = 729

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 729, x = - 729

729 = 27

- 729 = - 27

x = 27, x = - 27

2 r + 3 < 7 or - r + 9 \leq 2

2^{\frac{7}{6}} \cdot 3 2^{\frac{7}{6}}

\frac{7}{18} - \frac{4}{15}

9 - x = 11

2 x^{2} + 6 x - 56 = 0

What are the solutions to the equation 253692=29*12x*x ?
The solutions to the equation 253692=29*12x*x are x=27,x=-27
Find the zeros of 253692=29*12x*x
The zeros of 253692=29*12x*x are x=27,x=-27