What are the solutions to the equation 20^2+x^2=25^2 ?

The solutions to the equation 20^2+x^2=25^2 are x=15,x=-15

Find the zeros of 20^2+x^2=25^2

The zeros of 20^2+x^2=25^2 are x=15,x=-15

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2 0^{2} + x^{2} = 2 5^{2}

x = 15, x = - 15

Solution steps

2 0^{2} + x^{2} = 2 5^{2}

Move

2 0^{2}

to the right side

x^{2} = 225

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 225, x = - 225

225 = 15

- 225 = - 15

x = 15, x = - 15

(\frac{9}{16})^{2}

∣ 2 w - 1 ∣ < 11

(\frac{5 x}{y ^{4}})^{- 3}

x + 1 + x - 1 < 3 x

30 v + 50 x

What are the solutions to the equation 20^2+x^2=25^2 ?
The solutions to the equation 20^2+x^2=25^2 are x=15,x=-15
Find the zeros of 20^2+x^2=25^2
The zeros of 20^2+x^2=25^2 are x=15,x=-15