What are the solutions to the equation c^2-8c+15=0 ?

The solutions to the equation c^2-8c+15=0 are c=5,c=3

Find the zeros of c^2-8c+15=0

The zeros of c^2-8c+15=0 are c=5,c=3

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c^{2} - 8 c + 15 = 0

c = 5, c = 3

Solution steps

c^{2} - 8 c + 15 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

c_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, c_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

c = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

c = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

c = 5, c = 3

27 y + 15 z - 21

y^{2} - 12 y + 27

a^{2} - 3 a - 54

x (x + 6) = - 18

\frac{3 ( x - 5 )}{2} = \frac{2 ( x + 5 )}{3}

What are the solutions to the equation c^2-8c+15=0 ?
The solutions to the equation c^2-8c+15=0 are c=5,c=3
Find the zeros of c^2-8c+15=0
The zeros of c^2-8c+15=0 are c=5,c=3