c^2-8c+15=0

解

c^{2} - 8 c + 15 = 0

c = 5, c = 3

解答ステップ

c^{2} - 8 c + 15 = 0

解くとthe二次式

c_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

c_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

解を分離する

c_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, c_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

c = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

c = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

二次equationの解:

c = 5, c = 3