What are the solutions to the equation -2x^2-16x-31=0 ?

The solutions to the equation -2x^2-16x-31=0 are x=-(8+sqrt(2))/2 ,x=-(8-sqrt(2))/2

Find the zeros of -2x^2-16x-31=0

The zeros of -2x^2-16x-31=0 are x=-(8+sqrt(2))/2 ,x=-(8-sqrt(2))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} - 16 x - 31 = 0

x = - \frac{8 + 2}{2}, x = - \frac{8 - 2}{2}

Decimal Notation

x = - 4.70710 \dots, x = - 3.29289 \dots

Solution steps

- 2 x^{2} - 16 x - 31 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 ( - 2 ) ( - 31 )}{2 ( - 2 )}

(- 16)^{2} - 4 (- 2) (- 31) = 22

x_{1, 2} = \frac{- ( - 16 ) \pm 2 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 2}{2 ( - 2 )}, x_{2} = \frac{- ( - 16 ) - 2 2}{2 ( - 2 )}

x = \frac{- ( - 16 ) + 2 2}{2 ( - 2 )} : - \frac{8 + 2}{2}

x = \frac{- ( - 16 ) - 2 2}{2 ( - 2 )} : - \frac{8 - 2}{2}

The solutions to the quadratic equation are:

x = - \frac{8 + 2}{2}, x = - \frac{8 - 2}{2}

∣ 5 x - 2 ∣ < 6

\frac{75}{4}

169 x^{2} - 196 y^{2}

- \frac{5}{8} (- 1)^{3}

4.3 r = 4.11 + 4.6 r

What are the solutions to the equation -2x^2-16x-31=0 ?
The solutions to the equation -2x^2-16x-31=0 are x=-(8+sqrt(2))/2 ,x=-(8-sqrt(2))/2
Find the zeros of -2x^2-16x-31=0
The zeros of -2x^2-16x-31=0 are x=-(8+sqrt(2))/2 ,x=-(8-sqrt(2))/2