What are the solutions to the equation x^2-18x=-2x+64 ?

The solutions to the equation x^2-18x=-2x+64 are x=8(1+sqrt(2)),x=8(1-sqrt(2))

Find the zeros of x^2-18x=-2x+64

The zeros of x^2-18x=-2x+64 are x=8(1+sqrt(2)),x=8(1-sqrt(2))

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x^{2} - 18 x = - 2 x + 64

x = 8 (1 + 2), x = 8 (1 - 2)

Decimal Notation

x = 19.31370 \dots, x = - 3.31370 \dots

Solution steps

x^{2} - 18 x = - 2 x + 64

Move

64

to the left side

x^{2} - 18 x - 64 = - 2 x

Move

2 x

to the left side

x^{2} - 16 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot ( - 64 )}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot (- 64) = 162

x_{1, 2} = \frac{- ( - 16 ) \pm 16 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 16 2}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 16 2}{2 \cdot 1}

x = \frac{- ( - 16 ) + 16 2}{2 \cdot 1} : 8 (1 + 2)

x = \frac{- ( - 16 ) - 16 2}{2 \cdot 1} : 8 (1 - 2)

The solutions to the quadratic equation are:

x = 8 (1 + 2), x = 8 (1 - 2)

3 w - 3 = 4 w + 11

x^{2} - 22 x + 72

(\frac{4 x}{y})^{2}

- 4 i \cdot 5 i

\frac{x}{2} = 9

What are the solutions to the equation x^2-18x=-2x+64 ?
The solutions to the equation x^2-18x=-2x+64 are x=8(1+sqrt(2)),x=8(1-sqrt(2))
Find the zeros of x^2-18x=-2x+64
The zeros of x^2-18x=-2x+64 are x=8(1+sqrt(2)),x=8(1-sqrt(2))