What are the solutions to the equation t^2-21t-110=0 ?

The solutions to the equation t^2-21t-110=0 are t=(21+sqrt(881))/2 ,t=(21-sqrt(881))/2

Find the zeros of t^2-21t-110=0

The zeros of t^2-21t-110=0 are t=(21+sqrt(881))/2 ,t=(21-sqrt(881))/2

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t^{2} - 21 t - 110 = 0

t = \frac{21 + 881}{2}, t = \frac{21 - 881}{2}

Decimal Notation

t = 25.34082 \dots, t = - 4.34082 \dots

Solution steps

t^{2} - 21 t - 110 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 1 \cdot ( - 110 )}{2 \cdot 1}

(- 21)^{2} - 4 \cdot 1 \cdot (- 110) = 881

t_{1, 2} = \frac{- ( - 21 ) \pm 881}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 21 ) + 881}{2 \cdot 1}, t_{2} = \frac{- ( - 21 ) - 881}{2 \cdot 1}

t = \frac{- ( - 21 ) + 881}{2 \cdot 1} : \frac{21 + 881}{2}

t = \frac{- ( - 21 ) - 881}{2 \cdot 1} : \frac{21 - 881}{2}

The solutions to the quadratic equation are:

t = \frac{21 + 881}{2}, t = \frac{21 - 881}{2}

3 - 9

\frac{( 1 + x ) ( 1 - x )}{x} \leq 0

20 - 5 r = 20 - 5 r

2 x^{2} + 3 x - 9 = 0

x^{\frac{1}{2}} \cdot x

What are the solutions to the equation t^2-21t-110=0 ?
The solutions to the equation t^2-21t-110=0 are t=(21+sqrt(881))/2 ,t=(21-sqrt(881))/2
Find the zeros of t^2-21t-110=0
The zeros of t^2-21t-110=0 are t=(21+sqrt(881))/2 ,t=(21-sqrt(881))/2