What are the solutions to the equation (3x-2)^2=4 ?

The solutions to the equation (3x-2)^2=4 are x= 4/3 ,x=0

Find the zeros of (3x-2)^2=4

The zeros of (3x-2)^2=4 are x= 4/3 ,x=0

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(3 x - 2)^{2} = 4

x = \frac{4}{3}, x = 0

Decimal Notation

x = 1.33333 \dots, x = 0

Solution steps

(3 x - 2)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 2 = 4 : x = \frac{4}{3}

Solve

3 x - 2 = - 4 : x = 0

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = 0

\frac{3}{\frac{4}{3}}

\frac{5}{- 1}

(e^{- x})^{2}

\frac{x + 3}{3} - \frac{x}{2} = \frac{2 x - 3}{6}

a^{8} + 18 a^{4} + 81

What are the solutions to the equation (3x-2)^2=4 ?
The solutions to the equation (3x-2)^2=4 are x= 4/3 ,x=0
Find the zeros of (3x-2)^2=4
The zeros of (3x-2)^2=4 are x= 4/3 ,x=0