What is the answer to 3(2p-1)=p+13+3p-4 ?

The answer to 3(2p-1)=p+13+3p-4 is p=6

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3(2p-1)=p+13+3p-4

3 (2 p - 1) = p + 13 + 3 p - 4

p = 6

Solution steps

3 (2 p - 1) = p + 13 + 3 p - 4

Group like terms

3 (2 p - 1) = p + 3 p + 13 - 4

Add similar elements:

p + 3 p = 4 p

3 (2 p - 1) = 4 p + 13 - 4

Add/Subtract the numbers:

13 - 4 = 9

3 (2 p - 1) = 4 p + 9

Expand

3 (2 p - 1) : 6 p - 3

6 p - 3 = 4 p + 9

Move

3

to the right side

6 p = 4 p + 12

Move

4 p

to the left side

2 p = 12

Divide both sides by

2

p = 6

p^{2} - 12 p = 13

\frac{7 b}{4 b ^{- 2}}

z + 2 < 8

108 n^{2} + 36 n + 3

2 x^{2} - x - 10 \leq 0

What is the answer to 3(2p-1)=p+13+3p-4 ?
The answer to 3(2p-1)=p+13+3p-4 is p=6
Solve for p: 3(2p-1)=p+13+3p-4
The solution is p=6