What is (13k^2)/(6j^2k^2)*2jk^2 ?

The solution to (13k^2)/(6j^2k^2)*2jk^2 is (13k^2)/(3j)

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simplify (13k^2)/(6j^2k^2)*2jk^2

simplify

\frac{13 k ^{2}}{6 j ^{2} k ^{2}} \cdot 2 j k^{2}

\frac{13 k ^{2}}{3 j}

Solution steps

\frac{13 k ^{2}}{6 j ^{2} k ^{2}} \cdot 2 j k^{2}

Cancel the common factor:

k^{2}

= \frac{13}{6 j ^{2}} \cdot 2 j k^{2}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{13 \cdot 2 j k ^{2}}{6 j ^{2}}

Factor the number:

6 = 2 \cdot 3

= \frac{13 \cdot 2 j k ^{2}}{2 \cdot 3 j ^{2}}

Cancel the common factor:

2

= \frac{13 j k ^{2}}{3 j ^{2}}

Simplify

\frac{j}{j ^{2}} : \frac{1}{j}

= \frac{13 k ^{2}}{3 j}

\frac{- 5 x - 15}{2 x ^{2} + 5 x - 3}

6 x + 5 = 4 x - 9

- 7 < 5 - 2 x \leq - 2

(\frac{1}{3})^{\frac{3}{2}}

2 + 18

What is (13k^2)/(6j^2k^2)*2jk^2 ?
The solution to (13k^2)/(6j^2k^2)*2jk^2 is (13k^2)/(3j)