What are the solutions to the equation 2x^2-6x-(7x-21)=0 ?

The solutions to the equation 2x^2-6x-(7x-21)=0 are x= 7/2 ,x=3

Find the zeros of 2x^2-6x-(7x-21)=0

The zeros of 2x^2-6x-(7x-21)=0 are x= 7/2 ,x=3

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2 x^{2} - 6 x - (7 x - 21) = 0

x = \frac{7}{2}, x = 3

Decimal Notation

x = 3.5, x = 3

Solution steps

2 x^{2} - 6 x - (7 x - 21) = 0

Expand

2 x^{2} - 6 x - (7 x - 21) : 2 x^{2} - 13 x + 21

2 x^{2} - 13 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 2 \cdot 21}{2 \cdot 2}

(- 13)^{2} - 4 \cdot 2 \cdot 21 = 1

x_{1, 2} = \frac{- ( - 13 ) \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 1}{2 \cdot 2}, x_{2} = \frac{- ( - 13 ) - 1}{2 \cdot 2}

x = \frac{- ( - 13 ) + 1}{2 \cdot 2} : \frac{7}{2}

x = \frac{- ( - 13 ) - 1}{2 \cdot 2} : 3

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = 3

z^{- 11} \cdot z^{- 15}

\frac{3 x + 1}{x + 1} \leq 3

0.49

x^{3} + 3 x^{2} + 6 x + 8

3 x^{2} - 6 x + 8 = 0

What are the solutions to the equation 2x^2-6x-(7x-21)=0 ?
The solutions to the equation 2x^2-6x-(7x-21)=0 are x= 7/2 ,x=3
Find the zeros of 2x^2-6x-(7x-21)=0
The zeros of 2x^2-6x-(7x-21)=0 are x= 7/2 ,x=3