What are the solutions to the equation -3x^2-4x=0 ?

The solutions to the equation -3x^2-4x=0 are x=-4/3 ,x=0

Find the zeros of -3x^2-4x=0

The zeros of -3x^2-4x=0 are x=-4/3 ,x=0

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- 3 x^{2} - 4 x = 0

x = - \frac{4}{3}, x = 0

Decimal Notation

x = - 1.33333 \dots, x = 0

Solution steps

- 3 x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 3 ) \cdot 0}{2 ( - 3 )}

(- 4)^{2} - 4 (- 3) \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 ( - 3 )}, x_{2} = \frac{- ( - 4 ) - 4}{2 ( - 3 )}

x = \frac{- ( - 4 ) + 4}{2 ( - 3 )} : - \frac{4}{3}

x = \frac{- ( - 4 ) - 4}{2 ( - 3 )} : 0

The solutions to the quadratic equation are:

x = - \frac{4}{3}, x = 0

\frac{6 x ^{- 2} y ^{2}}{3 y ^{- 4}}

6 x^{2} - 2 x = x

(x - 1)^{2} = 49

4 x + 8 y

(x + 4) (x^{2} - 5 x)

What are the solutions to the equation -3x^2-4x=0 ?
The solutions to the equation -3x^2-4x=0 are x=-4/3 ,x=0
Find the zeros of -3x^2-4x=0
The zeros of -3x^2-4x=0 are x=-4/3 ,x=0