What are the solutions to the equation 5x^2-11x-39=3 ?

The solutions to the equation 5x^2-11x-39=3 are x= 21/5 ,x=-2

Find the zeros of 5x^2-11x-39=3

The zeros of 5x^2-11x-39=3 are x= 21/5 ,x=-2

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5 x^{2} - 11 x - 39 = 3

x = \frac{21}{5}, x = - 2

Decimal Notation

x = 4.2, x = - 2

Solution steps

5 x^{2} - 11 x - 39 = 3

Move

3

to the left side

5 x^{2} - 11 x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 5 ( - 42 )}{2 \cdot 5}

(- 11)^{2} - 4 \cdot 5 (- 42) = 31

x_{1, 2} = \frac{- ( - 11 ) \pm 31}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 31}{2 \cdot 5}, x_{2} = \frac{- ( - 11 ) - 31}{2 \cdot 5}

x = \frac{- ( - 11 ) + 31}{2 \cdot 5} : \frac{21}{5}

x = \frac{- ( - 11 ) - 31}{2 \cdot 5} : - 2

The solutions to the quadratic equation are:

x = \frac{21}{5}, x = - 2

4 y^{2} - 28 y - 72

- 8 + 4 \div 2 + 5

x y - 2 x + 4 y - 8

3 x^{2} + 48 = 0

(4^{\frac{1}{6}})^{3}

What are the solutions to the equation 5x^2-11x-39=3 ?
The solutions to the equation 5x^2-11x-39=3 are x= 21/5 ,x=-2
Find the zeros of 5x^2-11x-39=3
The zeros of 5x^2-11x-39=3 are x= 21/5 ,x=-2