What are the solutions to the equation 14x^2-33x-5=0 ?

The solutions to the equation 14x^2-33x-5=0 are x= 5/2 ,x=-1/7

Find the zeros of 14x^2-33x-5=0

The zeros of 14x^2-33x-5=0 are x= 5/2 ,x=-1/7

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14 x^{2} - 33 x - 5 = 0

x = \frac{5}{2}, x = - \frac{1}{7}

Decimal Notation

x = 2.5, x = - 0.14285 \dots

Solution steps

14 x^{2} - 33 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 33 ) \pm ( - 33 ) ^{2} - 4 \cdot 14 ( - 5 )}{2 \cdot 14}

(- 33)^{2} - 4 \cdot 14 (- 5) = 37

x_{1, 2} = \frac{- ( - 33 ) \pm 37}{2 \cdot 14}

Separate the solutions

x_{1} = \frac{- ( - 33 ) + 37}{2 \cdot 14}, x_{2} = \frac{- ( - 33 ) - 37}{2 \cdot 14}

x = \frac{- ( - 33 ) + 37}{2 \cdot 14} : \frac{5}{2}

x = \frac{- ( - 33 ) - 37}{2 \cdot 14} : - \frac{1}{7}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{1}{7}

- \frac{3}{4} (16 x + 8) = 9 - (10 x - 3)

3 x - 10 \geq 2

\frac{x ^{2} + 3 x + 2}{x + 1}

160 x^{2} - 111 x + 27 = 0

50 x^{2} + 45 x y - 18 y^{2}

What are the solutions to the equation 14x^2-33x-5=0 ?
The solutions to the equation 14x^2-33x-5=0 are x= 5/2 ,x=-1/7
Find the zeros of 14x^2-33x-5=0
The zeros of 14x^2-33x-5=0 are x= 5/2 ,x=-1/7