What is (x^2-y^2)/(4x+4y)*(x+y)/(x-y) ?

The solution to (x^2-y^2)/(4x+4y)*(x+y)/(x-y) is (x+y)/4

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simplify (x^2-y^2)/(4x+4y)*(x+y)/(x-y)

simplify

\frac{x ^{2} - y ^{2}}{4 x + 4 y} \cdot \frac{x + y}{x - y}

\frac{x + y}{4}

Solution steps

\frac{x ^{2} - y ^{2}}{4 x + 4 y} \cdot \frac{x + y}{x - y}

Cancel

\frac{x ^{2} - y ^{2}}{4 x + 4 y} : \frac{x - y}{4}

= \frac{x - y}{4} \cdot \frac{x + y}{x - y}

Cross-cancel common factor:

x - y

= \frac{x + y}{4}

\frac{1}{3} x - \frac{2}{3} = - 18

(\frac{( x ^{2} )}{2})^{2}

5 yz - 10 x y + 10 x y^{2} z

\frac{- x ^{2}}{x ^{2}}

4^{\frac{1}{2}} + 6 4^{\frac{2}{3}} \cdot 1 6^{\frac{1}{4}}

What is (x^2-y^2)/(4x+4y)*(x+y)/(x-y) ?
The solution to (x^2-y^2)/(4x+4y)*(x+y)/(x-y) is (x+y)/4