What are the solutions to the equation 3x^2+27x=30 ?

The solutions to the equation 3x^2+27x=30 are x=1,x=-10

Find the zeros of 3x^2+27x=30

The zeros of 3x^2+27x=30 are x=1,x=-10

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3 x^{2} + 27 x = 30

x = 1, x = - 10

Solution steps

3 x^{2} + 27 x = 30

Move

30

to the left side

3 x^{2} + 27 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 27 \pm 2 7 ^{2} - 4 \cdot 3 ( - 30 )}{2 \cdot 3}

2 7^{2} - 4 \cdot 3 (- 30) = 33

x_{1, 2} = \frac{- 27 \pm 33}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 27 + 33}{2 \cdot 3}, x_{2} = \frac{- 27 - 33}{2 \cdot 3}

x = \frac{- 27 + 33}{2 \cdot 3} : 1

x = \frac{- 27 - 33}{2 \cdot 3} : - 10

The solutions to the quadratic equation are:

x = 1, x = - 10

\frac{1}{3} + \frac{1}{2} + \frac{1}{4}

\frac{7 x + 1}{x - 1} = 4

0 = x^{2} - 5 x - 4

0 = 6 - 6 x - x^{2}

∣ 2 x + 3 ∣ = 10

What are the solutions to the equation 3x^2+27x=30 ?
The solutions to the equation 3x^2+27x=30 are x=1,x=-10
Find the zeros of 3x^2+27x=30
The zeros of 3x^2+27x=30 are x=1,x=-10