What are the solutions to the equation 11x^2+9x+4=0 ?

The solutions to the equation 11x^2+9x+4=0 are x=-9/22+i(sqrt(95))/(22),x=-9/22-i(sqrt(95))/(22)

Find the zeros of 11x^2+9x+4=0

The zeros of 11x^2+9x+4=0 are x=-9/22+i(sqrt(95))/(22),x=-9/22-i(sqrt(95))/(22)

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11 x^{2} + 9 x + 4 = 0

x = - \frac{9}{22} + i \frac{95}{22}, x = - \frac{9}{22} - i \frac{95}{22}

Solution steps

11 x^{2} + 9 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 11 \cdot 4}{2 \cdot 11}

Simplify

9^{2} - 4 \cdot 11 \cdot 4 : 95 i

x_{1, 2} = \frac{- 9 \pm 95 i}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- 9 + 95 i}{2 \cdot 11}, x_{2} = \frac{- 9 - 95 i}{2 \cdot 11}

x = \frac{- 9 + 95 i}{2 \cdot 11} : - \frac{9}{22} + i \frac{95}{22}

x = \frac{- 9 - 95 i}{2 \cdot 11} : - \frac{9}{22} - i \frac{95}{22}

The solutions to the quadratic equation are:

x = - \frac{9}{22} + i \frac{95}{22}, x = - \frac{9}{22} - i \frac{95}{22}

\frac{x}{5} = 5 + \frac{x - 4}{2}

6 p + 2 (p - 1) = 22

\frac{x ^{3} + 2 x ^{2} - 4 x - 8}{x + 9} \leq 0

4 x^{2} - 8 x - 5 = 0

5 x^{2} + (3 x - 6) = 0

What are the solutions to the equation 11x^2+9x+4=0 ?
The solutions to the equation 11x^2+9x+4=0 are x=-9/22+i(sqrt(95))/(22),x=-9/22-i(sqrt(95))/(22)
Find the zeros of 11x^2+9x+4=0
The zeros of 11x^2+9x+4=0 are x=-9/22+i(sqrt(95))/(22),x=-9/22-i(sqrt(95))/(22)