What are the solutions to the equation 2x^2=2 ?

The solutions to the equation 2x^2=2 are x=1,x=-1

Find the zeros of 2x^2=2

The zeros of 2x^2=2 are x=1,x=-1

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2 x^{2} = 2

x = 1, x = - 1

Solution steps

2 x^{2} = 2

Divide both sides by

2

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

6 x^{2} - x^{2} - 20

- 3 n > 15 or 3 n + 6 > 15

2.5 x - 10 = 25

9 \leq 2 x + 8 < 12

- 2 x = - 14

What are the solutions to the equation 2x^2=2 ?
The solutions to the equation 2x^2=2 are x=1,x=-1
Find the zeros of 2x^2=2
The zeros of 2x^2=2 are x=1,x=-1