What are the solutions to the equation 2x^2+42+9x=50x-3x^2 ?

The solutions to the equation 2x^2+42+9x=50x-3x^2 are x=7,x= 6/5

Find the zeros of 2x^2+42+9x=50x-3x^2

The zeros of 2x^2+42+9x=50x-3x^2 are x=7,x= 6/5

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2 x^{2} + 42 + 9 x = 50 x - 3 x^{2}

x = 7, x = \frac{6}{5}

Decimal Notation

x = 7, x = 1.2

Solution steps

2 x^{2} + 42 + 9 x = 50 x - 3 x^{2}

Move

3 x^{2}

to the left side

5 x^{2} + 9 x + 42 = 50 x

Move

50 x

to the left side

5 x^{2} - 41 x + 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 41 ) \pm ( - 41 ) ^{2} - 4 \cdot 5 \cdot 42}{2 \cdot 5}

(- 41)^{2} - 4 \cdot 5 \cdot 42 = 29

x_{1, 2} = \frac{- ( - 41 ) \pm 29}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 41 ) + 29}{2 \cdot 5}, x_{2} = \frac{- ( - 41 ) - 29}{2 \cdot 5}

x = \frac{- ( - 41 ) + 29}{2 \cdot 5} : 7

x = \frac{- ( - 41 ) - 29}{2 \cdot 5} : \frac{6}{5}

The solutions to the quadratic equation are:

x = 7, x = \frac{6}{5}

\frac{2}{\frac{2}{5}}

7 (4 - 5 x) = 13

4 q^{2} - 3 pq - 4 q + 3 p

lo g_{11} (16)

∣ x - 4 ∣ = ∣ 3 x + 7 ∣

What are the solutions to the equation 2x^2+42+9x=50x-3x^2 ?
The solutions to the equation 2x^2+42+9x=50x-3x^2 are x=7,x= 6/5
Find the zeros of 2x^2+42+9x=50x-3x^2
The zeros of 2x^2+42+9x=50x-3x^2 are x=7,x= 6/5