What are the solutions to the equation (2x+5)^2=9 ?

The solutions to the equation (2x+5)^2=9 are x=-1,x=-4

Find the zeros of (2x+5)^2=9

The zeros of (2x+5)^2=9 are x=-1,x=-4

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(2 x + 5)^{2} = 9

x = - 1, x = - 4

Solution steps

(2 x + 5)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 5 = 9 : x = - 1

Solve

2 x + 5 = - 9 : x = - 4

The solutions to the quadratic equation are:

x = - 1, x = - 4

2 y^{2} + 11 y + 5

\frac{4 - ( 1 + i ) ^{2}}{2 ( 1 + i )}

7 = \frac{y}{17.5}

- 5 + \frac{1}{4} x = 3 x + 6

\frac{y}{3} + \frac{5}{8} = \frac{y}{8} - \frac{5}{8}

What are the solutions to the equation (2x+5)^2=9 ?
The solutions to the equation (2x+5)^2=9 are x=-1,x=-4
Find the zeros of (2x+5)^2=9
The zeros of (2x+5)^2=9 are x=-1,x=-4