What are the solutions to the equation x^2+7x+7=0 ?

The solutions to the equation x^2+7x+7=0 are x=(-7+sqrt(21))/2 ,x=(-7-sqrt(21))/2

Find the zeros of x^2+7x+7=0

The zeros of x^2+7x+7=0 are x=(-7+sqrt(21))/2 ,x=(-7-sqrt(21))/2

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x^{2} + 7 x + 7 = 0

x = \frac{- 7 + 21}{2}, x = \frac{- 7 - 21}{2}

Decimal Notation

x = - 1.20871 \dots, x = - 5.79128 \dots

Solution steps

x^{2} + 7 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 7 = 21

x_{1, 2} = \frac{- 7 \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 21}{2 \cdot 1}, x_{2} = \frac{- 7 - 21}{2 \cdot 1}

x = \frac{- 7 + 21}{2 \cdot 1} : \frac{- 7 + 21}{2}

x = \frac{- 7 - 21}{2 \cdot 1} : \frac{- 7 - 21}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 21}{2}, x = \frac{- 7 - 21}{2}

x^{3} - 3 x^{2} y + 3 x y^{2} - y^{3}

12 x + 4

12 x^{2} - 88 x + 112

3 (X - 1) + 2 (X + 2) - 5 = 4 X + 6

\frac{5}{6} \cdot (2 x - 1) - x = \frac{x}{6}

What are the solutions to the equation x^2+7x+7=0 ?
The solutions to the equation x^2+7x+7=0 are x=(-7+sqrt(21))/2 ,x=(-7-sqrt(21))/2
Find the zeros of x^2+7x+7=0
The zeros of x^2+7x+7=0 are x=(-7+sqrt(21))/2 ,x=(-7-sqrt(21))/2