6m^2>15-m

Solution

6 m^{2} > 15 - m

m < - \frac{5}{3} or m > \frac{3}{2}

Interval Notation

(- \infty, - \frac{5}{3}) \cup (\frac{3}{2}, \infty)

Decimal Notation

m < - 1.66666 \dots or m > 1.5

Solution steps

6 m^{2} > 15 - m

Rewrite in standard form

6 m^{2} + m - 15 > 0

Factor

6 m^{2} + m - 15 : (2 m - 3) (3 m + 5)

(2 m - 3) (3 m + 5) > 0

Identify the intervals

m < - \frac{5}{3} or m > \frac{3}{2}

0 = - 0.000007 t^{2} - 0.001082 t + 1.97817

g^{2} - 3 g = 4

\frac{z ^{- 7}}{z ^{- 9}}

- 4 x^{2} - 12 x + 8

- 80 - 980