What are the solutions to the equation x^2+4=4x ?

The solutions to the equation x^2+4=4x are x=2

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x^2+4=4x

x^{2} + 4 = 4 x

x = 2

Solution steps

x^{2} + 4 = 4 x

Move

4 x

to the left side

x^{2} + 4 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

x (x - 1) + x (x - 3) < 48

(- 2 \frac{1}{2})^{2}

2 m^{6} - 24 m^{5} + 64 m^{4}

3 x + 1 > 0

w^{2} - 5 w + 3 = 0

What are the solutions to the equation x^2+4=4x ?
The solutions to the equation x^2+4=4x are x=2
Find the zeros of x^2+4=4x
The zeros of x^2+4=4x are x=2