What are the solutions to the equation w^2-5w+3=0 ?

The solutions to the equation w^2-5w+3=0 are w=(5+sqrt(13))/2 ,w=(5-sqrt(13))/2

Find the zeros of w^2-5w+3=0

The zeros of w^2-5w+3=0 are w=(5+sqrt(13))/2 ,w=(5-sqrt(13))/2

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w^{2} - 5 w + 3 = 0

w = \frac{5 + 13}{2}, w = \frac{5 - 13}{2}

Solution steps

w^{2} - 5 w + 3 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 3 = 13

w_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 1}, w_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 1}

w = \frac{- ( - 5 ) + 13}{2 \cdot 1} : \frac{5 + 13}{2}

w = \frac{- ( - 5 ) - 13}{2 \cdot 1} : \frac{5 - 13}{2}

The solutions to the quadratic equation are:

w = \frac{5 + 13}{2}, w = \frac{5 - 13}{2}

(x - 6)^{2} = 36

∣ 3 x - 1 ∣ = 2 x + 5

- 4 x + 10 \geq - 7

v^{2} - 16

2 (4 v - 1) < 2 (3 v + 1)

What are the solutions to the equation w^2-5w+3=0 ?
The solutions to the equation w^2-5w+3=0 are w=(5+sqrt(13))/2 ,w=(5-sqrt(13))/2
Find the zeros of w^2-5w+3=0
The zeros of w^2-5w+3=0 are w=(5+sqrt(13))/2 ,w=(5-sqrt(13))/2