What are the solutions to the equation x^2+11x-900=0 ?

The solutions to the equation x^2+11x-900=0 are x=25,x=-36

Find the zeros of x^2+11x-900=0

The zeros of x^2+11x-900=0 are x=25,x=-36

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x^{2} + 11 x - 900 = 0

x = 25, x = - 36

Solution steps

x^{2} + 11 x - 900 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot ( - 900 )}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot (- 900) = 61

x_{1, 2} = \frac{- 11 \pm 61}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 61}{2 \cdot 1}, x_{2} = \frac{- 11 - 61}{2 \cdot 1}

x = \frac{- 11 + 61}{2 \cdot 1} : 25

x = \frac{- 11 - 61}{2 \cdot 1} : - 36

The solutions to the quadratic equation are:

x = 25, x = - 36

z^{2} - \frac{3}{2} z + \frac{9}{16} = 0

2 (x + 1)^{2} + 6 = 134

5 m^{2} + 20 m + 40

8 a^{3} + 4 a

\frac{2}{7} + \frac{2}{3}

What are the solutions to the equation x^2+11x-900=0 ?
The solutions to the equation x^2+11x-900=0 are x=25,x=-36
Find the zeros of x^2+11x-900=0
The zeros of x^2+11x-900=0 are x=25,x=-36