What are the solutions to the equation 2(x+1)^2+6=134 ?

The solutions to the equation 2(x+1)^2+6=134 are x=7,x=-9

Find the zeros of 2(x+1)^2+6=134

The zeros of 2(x+1)^2+6=134 are x=7,x=-9

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2 (x + 1)^{2} + 6 = 134

x = 7, x = - 9

Solution steps

2 (x + 1)^{2} + 6 = 134

Move

6

to the right side

2 (x + 1)^{2} = 128

Divide both sides by

2

(x + 1)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 64 : x = 7

Solve

x + 1 = - 64 : x = - 9

The solutions to the quadratic equation are:

x = 7, x = - 9

5 m^{2} + 20 m + 40

8 a^{3} + 4 a

\frac{2}{7} + \frac{2}{3}

6 x + 35 = - 6 x - 35

(8 - 3 i)^{2}

What are the solutions to the equation 2(x+1)^2+6=134 ?
The solutions to the equation 2(x+1)^2+6=134 are x=7,x=-9
Find the zeros of 2(x+1)^2+6=134
The zeros of 2(x+1)^2+6=134 are x=7,x=-9