What are the solutions to the equation (x-3)^2+9=25 ?

The solutions to the equation (x-3)^2+9=25 are x=7,x=-1

Find the zeros of (x-3)^2+9=25

The zeros of (x-3)^2+9=25 are x=7,x=-1

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(x - 3)^{2} + 9 = 25

x = 7, x = - 1

Solution steps

(x - 3)^{2} + 9 = 25

Move

9

to the right side

(x - 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 16 : x = 7

Solve

x - 3 = - 16 : x = - 1

The solutions to the quadratic equation are:

x = 7, x = - 1

- 4 + 3 x - 5 x = - 1 - 10 + x

∣ x ∣ = 7

\frac{x - \frac{x}{y}}{y - \frac{y}{x}}

\frac{- 3}{- 4 + 5 i}

lo g_{3} (a^{7}) + (lo g_{3} (a^{4}) - 2 \cdot lo g_{3} (b))

What are the solutions to the equation (x-3)^2+9=25 ?
The solutions to the equation (x-3)^2+9=25 are x=7,x=-1
Find the zeros of (x-3)^2+9=25
The zeros of (x-3)^2+9=25 are x=7,x=-1