What are the solutions to the equation (s^2-4s+20)=0 ?

The solutions to the equation (s^2-4s+20)=0 are s=2+4i,s=2-4i

Find the zeros of (s^2-4s+20)=0

The zeros of (s^2-4s+20)=0 are s=2+4i,s=2-4i

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(s^{2} - 4 s + 20) = 0

s = 2 + 4 i, s = 2 - 4 i

Solution steps

(s^{2} - 4 s + 20) = 0

Refine

s^{2} - 4 s + 20 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 20 : 8 i

s_{1, 2} = \frac{- ( - 4 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 4 ) + 8 i}{2 \cdot 1}, s_{2} = \frac{- ( - 4 ) - 8 i}{2 \cdot 1}

s = \frac{- ( - 4 ) + 8 i}{2 \cdot 1} : 2 + 4 i

s = \frac{- ( - 4 ) - 8 i}{2 \cdot 1} : 2 - 4 i

The solutions to the quadratic equation are:

s = 2 + 4 i, s = 2 - 4 i

7 (2 x + 4) = 42

j - 8 > - 12

64 - 27 y^{3}

11 y^{2} - 19 y - 10 = - 4 y^{2}

- 1 2^{2} + x^{2} = 1 3^{2}

What are the solutions to the equation (s^2-4s+20)=0 ?
The solutions to the equation (s^2-4s+20)=0 are s=2+4i,s=2-4i
Find the zeros of (s^2-4s+20)=0
The zeros of (s^2-4s+20)=0 are s=2+4i,s=2-4i