What are the solutions to the equation 5x^2-39x-8=0 ?

The solutions to the equation 5x^2-39x-8=0 are x=8,x=-1/5

Find the zeros of 5x^2-39x-8=0

The zeros of 5x^2-39x-8=0 are x=8,x=-1/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} - 39 x - 8 = 0

x = 8, x = - \frac{1}{5}

Solution steps

5 x^{2} - 39 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 39 ) \pm ( - 39 ) ^{2} - 4 \cdot 5 ( - 8 )}{2 \cdot 5}

(- 39)^{2} - 4 \cdot 5 (- 8) = 41

x_{1, 2} = \frac{- ( - 39 ) \pm 41}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 39 ) + 41}{2 \cdot 5}, x_{2} = \frac{- ( - 39 ) - 41}{2 \cdot 5}

x = \frac{- ( - 39 ) + 41}{2 \cdot 5} : 8

x = \frac{- ( - 39 ) - 41}{2 \cdot 5} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = 8, x = - \frac{1}{5}

\frac{2}{3} + 3

- - 19

16 - 40 x^{4}

x + 7 \geq 18

\frac{118}{2%} ((1 + 12%)^{6} - (1 + 10%)^{6})

What are the solutions to the equation 5x^2-39x-8=0 ?
The solutions to the equation 5x^2-39x-8=0 are x=8,x=-1/5
Find the zeros of 5x^2-39x-8=0
The zeros of 5x^2-39x-8=0 are x=8,x=-1/5