What are the solutions to the equation 10x^2-40x-60=0 ?

The solutions to the equation 10x^2-40x-60=0 are x=2+sqrt(10),x=2-sqrt(10)

Find the zeros of 10x^2-40x-60=0

The zeros of 10x^2-40x-60=0 are x=2+sqrt(10),x=2-sqrt(10)

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10 x^{2} - 40 x - 60 = 0

x = 2 + 10, x = 2 - 10

Decimal Notation

x = 5.16227 \dots, x = - 1.16227 \dots

Solution steps

10 x^{2} - 40 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 10 ( - 60 )}{2 \cdot 10}

(- 40)^{2} - 4 \cdot 10 (- 60) = 2010

x_{1, 2} = \frac{- ( - 40 ) \pm 20 10}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 20 10}{2 \cdot 10}, x_{2} = \frac{- ( - 40 ) - 20 10}{2 \cdot 10}

x = \frac{- ( - 40 ) + 20 10}{2 \cdot 10} : 2 + 10

x = \frac{- ( - 40 ) - 20 10}{2 \cdot 10} : 2 - 10

The solutions to the quadratic equation are:

x = 2 + 10, x = 2 - 10

\frac{1}{2} (x - \frac{1}{3}) = \frac{3}{4} - \frac{x}{6}

\frac{8 π}{6}

\frac{4 ! 6 !}{5 ! 3 !}

x^{2} y^{3} + x^{5} y^{4}

What are the solutions to the equation 10x^2-40x-60=0 ?
The solutions to the equation 10x^2-40x-60=0 are x=2+sqrt(10),x=2-sqrt(10)
Find the zeros of 10x^2-40x-60=0
The zeros of 10x^2-40x-60=0 are x=2+sqrt(10),x=2-sqrt(10)