What are the solutions to the equation 18x^2+47x+5=0 ?

The solutions to the equation 18x^2+47x+5=0 are x=-1/9 ,x=-5/2

Find the zeros of 18x^2+47x+5=0

The zeros of 18x^2+47x+5=0 are x=-1/9 ,x=-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

18 x^{2} + 47 x + 5 = 0

x = - \frac{1}{9}, x = - \frac{5}{2}

Solution steps

18 x^{2} + 47 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 47 \pm 4 7 ^{2} - 4 \cdot 18 \cdot 5}{2 \cdot 18}

4 7^{2} - 4 \cdot 18 \cdot 5 = 43

x_{1, 2} = \frac{- 47 \pm 43}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- 47 + 43}{2 \cdot 18}, x_{2} = \frac{- 47 - 43}{2 \cdot 18}

x = \frac{- 47 + 43}{2 \cdot 18} : - \frac{1}{9}

x = \frac{- 47 - 43}{2 \cdot 18} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{9}, x = - \frac{5}{2}

\frac{3}{4} x + \frac{9}{2} \geq \frac{7}{2} + \frac{11}{4}

- x - 1 = 4 x - 11

- 20 x^{10} - 2 x^{5} + 4

\frac{x - 7}{4} + \frac{25 ( x - 2 )}{3} = \frac{5 x + 35}{4} + \frac{5}{2} (x - 7)

12 ab x^{2} + 6 a^{2} b x^{3} - 30 a b^{3}

What are the solutions to the equation 18x^2+47x+5=0 ?
The solutions to the equation 18x^2+47x+5=0 are x=-1/9 ,x=-5/2
Find the zeros of 18x^2+47x+5=0
The zeros of 18x^2+47x+5=0 are x=-1/9 ,x=-5/2