What is 3/4 x+9/2 >= 7/2+11/4 ?

The solution to 3/4 x+9/2 >= 7/2+11/4 is x>= 7/3

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3/4 x+9/2 >= 7/2+11/4

\frac{3}{4} x + \frac{9}{2} \geq \frac{7}{2} + \frac{11}{4}

x \geq \frac{7}{3}

Solution steps

\frac{3}{4} x + \frac{9}{2} \geq \frac{7}{2} + \frac{11}{4}

Simplify

\frac{7}{2} + \frac{11}{4} : \frac{25}{4}

\frac{3}{4} x + \frac{9}{2} \geq \frac{25}{4}

Move

\frac{9}{2}

to the right side

\frac{3}{4} x \geq \frac{7}{4}

Multiply both sides by

4

3 x \geq 7

Divide both sides by

3

x \geq \frac{7}{3}

- x - 1 = 4 x - 11

- 20 x^{10} - 2 x^{5} + 4

\frac{x - 7}{4} + \frac{25 ( x - 2 )}{3} = \frac{5 x + 35}{4} + \frac{5}{2} (x - 7)

12 ab x^{2} + 6 a^{2} b x^{3} - 30 a b^{3}

35

What is 3/4 x+9/2 >= 7/2+11/4 ?
The solution to 3/4 x+9/2 >= 7/2+11/4 is x>= 7/3