What are the solutions to the equation 7x^2+63x=0 ?

The solutions to the equation 7x^2+63x=0 are x=0,x=-9

Find the zeros of 7x^2+63x=0

The zeros of 7x^2+63x=0 are x=0,x=-9

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7 x^{2} + 63 x = 0

x = 0, x = - 9

Solution steps

7 x^{2} + 63 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 63 \pm 6 3 ^{2} - 4 \cdot 7 \cdot 0}{2 \cdot 7}

6 3^{2} - 4 \cdot 7 \cdot 0 = 63

x_{1, 2} = \frac{- 63 \pm 63}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 63 + 63}{2 \cdot 7}, x_{2} = \frac{- 63 - 63}{2 \cdot 7}

x = \frac{- 63 + 63}{2 \cdot 7} : 0

x = \frac{- 63 - 63}{2 \cdot 7} : - 9

The solutions to the quadratic equation are:

x = 0, x = - 9

(m + 2) (3 m + 10) = 3 (m + 5) + 15

1 - \frac{1}{3}

\frac{1}{4} (1 + 3 (- 0.33))

4 - 6 x = x - 24

- \frac{2}{3} (\frac{6}{5} x - \frac{7}{10}) = \frac{17}{20}

What are the solutions to the equation 7x^2+63x=0 ?
The solutions to the equation 7x^2+63x=0 are x=0,x=-9
Find the zeros of 7x^2+63x=0
The zeros of 7x^2+63x=0 are x=0,x=-9