What is 1/(3-2x)> 1/(4-5x) ?

The solution to 1/(3-2x)> 1/(4-5x) is x< 1/3 \lor 4/5 <x< 3/2

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1/(3-2x)> 1/(4-5x)

\frac{1}{3 - 2 x} > \frac{1}{4 - 5 x}

x < \frac{1}{3} or \frac{4}{5} < x < \frac{3}{2}

Solution steps

\frac{1}{3 - 2 x} > \frac{1}{4 - 5 x}

Rewrite in standard form

\frac{- 3 x + 1}{( - 2 x + 3 ) ( - 5 x + 4 )} > 0

Identify the intervals

x < \frac{1}{3} or \frac{4}{5} < x < \frac{3}{2}

\frac{7 m ^{5} n ^{- 7}}{a ^{2} m ^{3} n ^{- 4}}

\frac{4 ( x ^{2} - 1 )}{x - 3} \leq x + 1

\frac{3 20}{2 4}

\frac{- 4}{5}

(\frac{15}{17})^{2} - (\frac{8}{17})^{2}

What is 1/(3-2x)> 1/(4-5x) ?
The solution to 1/(3-2x)> 1/(4-5x) is x< 1/3 \lor 4/5 <x< 3/2