What are the solutions to the equation 3x^2=3-42x ?

The solutions to the equation 3x^2=3-42x are x=-7+5sqrt(2),x=-7-5sqrt(2)

Find the zeros of 3x^2=3-42x

The zeros of 3x^2=3-42x are x=-7+5sqrt(2),x=-7-5sqrt(2)

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3 x^{2} = 3 - 42 x

x = - 7 + 52, x = - 7 - 52

Solution steps

3 x^{2} = 3 - 42 x

Move

42 x

to the left side

3 x^{2} + 42 x = 3

Move

3

to the left side

3 x^{2} + 42 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 42 \pm 4 2 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

4 2^{2} - 4 \cdot 3 (- 3) = 302

x_{1, 2} = \frac{- 42 \pm 30 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 42 + 30 2}{2 \cdot 3}, x_{2} = \frac{- 42 - 30 2}{2 \cdot 3}

x = \frac{- 42 + 30 2}{2 \cdot 3} : - 7 + 52

x = \frac{- 42 - 30 2}{2 \cdot 3} : - 7 - 52

The solutions to the quadratic equation are:

x = - 7 + 52, x = - 7 - 52

- \frac{4}{3 i}

2 x^{2} - 4 x - 9 = 0

((\frac{1}{16})^{- \frac{2}{3}})^{\frac{3}{4}}

What are the solutions to the equation 3x^2=3-42x ?
The solutions to the equation 3x^2=3-42x are x=-7+5sqrt(2),x=-7-5sqrt(2)
Find the zeros of 3x^2=3-42x
The zeros of 3x^2=3-42x are x=-7+5sqrt(2),x=-7-5sqrt(2)