What are the solutions to the equation y^2-10y=-18 ?

The solutions to the equation y^2-10y=-18 are y=5+sqrt(7),y=5-sqrt(7)

Find the zeros of y^2-10y=-18

The zeros of y^2-10y=-18 are y=5+sqrt(7),y=5-sqrt(7)

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y^{2} - 10 y = - 18

y = 5 + 7, y = 5 - 7

Decimal Notation

y = 7.64575 \dots, y = 2.35424 \dots

Solution steps

y^{2} - 10 y = - 18

Move

18

to the left side

y^{2} - 10 y + 18 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 18 = 27

y_{1, 2} = \frac{- ( - 10 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 10 ) + 2 7}{2 \cdot 1}, y_{2} = \frac{- ( - 10 ) - 2 7}{2 \cdot 1}

y = \frac{- ( - 10 ) + 2 7}{2 \cdot 1} : 5 + 7

y = \frac{- ( - 10 ) - 2 7}{2 \cdot 1} : 5 - 7

The solutions to the quadratic equation are:

y = 5 + 7, y = 5 - 7

A^{2} - B^{2} - 12 B - 36

(4 + 35) \cdot (- 2 + 5)

(7 x)^{- \frac{1}{3}}

5 x - 2 = 57

5 x^{2} + 19 x + 2 = 0

What are the solutions to the equation y^2-10y=-18 ?
The solutions to the equation y^2-10y=-18 are y=5+sqrt(7),y=5-sqrt(7)
Find the zeros of y^2-10y=-18
The zeros of y^2-10y=-18 are y=5+sqrt(7),y=5-sqrt(7)