What are the solutions to the equation 2x^2-11x-6=0 ?

The solutions to the equation 2x^2-11x-6=0 are x=6,x=-1/2

Find the zeros of 2x^2-11x-6=0

The zeros of 2x^2-11x-6=0 are x=6,x=-1/2

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2 x^{2} - 11 x - 6 = 0

x = 6, x = - \frac{1}{2}

Solution steps

2 x^{2} - 11 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 (- 6) = 13

x_{1, 2} = \frac{- ( - 11 ) \pm 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 13}{2 \cdot 2}, x_{2} = \frac{- ( - 11 ) - 13}{2 \cdot 2}

x = \frac{- ( - 11 ) + 13}{2 \cdot 2} : 6

x = \frac{- ( - 11 ) - 13}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 6, x = - \frac{1}{2}

- \frac{π}{4} + \frac{π}{4}

3 (x + 2) \cdot 10 \cdot \frac{7}{70} - 2 (x + 2)

\frac{d}{3} + 1 \geq - 1

(\frac{1}{2})^{\frac{1}{4}}

2 x^{2} + 14 x - 120

What are the solutions to the equation 2x^2-11x-6=0 ?
The solutions to the equation 2x^2-11x-6=0 are x=6,x=-1/2
Find the zeros of 2x^2-11x-6=0
The zeros of 2x^2-11x-6=0 are x=6,x=-1/2