What are the solutions to the equation x^2+3x=-1 ?

The solutions to the equation x^2+3x=-1 are x=(-3+sqrt(5))/2 ,x=(-3-sqrt(5))/2

Find the zeros of x^2+3x=-1

The zeros of x^2+3x=-1 are x=(-3+sqrt(5))/2 ,x=(-3-sqrt(5))/2

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x^{2} + 3 x = - 1

x = \frac{- 3 + 5}{2}, x = \frac{- 3 - 5}{2}

Solution steps

x^{2} + 3 x = - 1

Move

1

to the left side

x^{2} + 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 1 = 5

x_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 5}{2 \cdot 1}, x_{2} = \frac{- 3 - 5}{2 \cdot 1}

x = \frac{- 3 + 5}{2 \cdot 1} : \frac{- 3 + 5}{2}

x = \frac{- 3 - 5}{2 \cdot 1} : \frac{- 3 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 5}{2}, x = \frac{- 3 - 5}{2}

- 5 (2 y - 15) + 4 y = 3

4 x^{2} + 28 x + 48

2 x^{4} + 3 x^{3} - 9 x^{2} + x + 3

∣ 3 x + 5 ∣ \geq 1

- 2 x^{2} + 5 x + 6 = 4 x^{2} + 5 x

What are the solutions to the equation x^2+3x=-1 ?
The solutions to the equation x^2+3x=-1 are x=(-3+sqrt(5))/2 ,x=(-3-sqrt(5))/2
Find the zeros of x^2+3x=-1
The zeros of x^2+3x=-1 are x=(-3+sqrt(5))/2 ,x=(-3-sqrt(5))/2