What are the solutions to the equation 7x^2-2x-5=0 ?

The solutions to the equation 7x^2-2x-5=0 are x=1,x=-5/7

Find the zeros of 7x^2-2x-5=0

The zeros of 7x^2-2x-5=0 are x=1,x=-5/7

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7 x^{2} - 2 x - 5 = 0

x = 1, x = - \frac{5}{7}

Decimal Notation

x = 1, x = - 0.71428 \dots

Solution steps

7 x^{2} - 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 7 ( - 5 )}{2 \cdot 7}

(- 2)^{2} - 4 \cdot 7 (- 5) = 12

x_{1, 2} = \frac{- ( - 2 ) \pm 12}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 12}{2 \cdot 7}, x_{2} = \frac{- ( - 2 ) - 12}{2 \cdot 7}

x = \frac{- ( - 2 ) + 12}{2 \cdot 7} : 1

x = \frac{- ( - 2 ) - 12}{2 \cdot 7} : - \frac{5}{7}

The solutions to the quadratic equation are:

x = 1, x = - \frac{5}{7}

\frac{3}{4} \cdot 12

\frac{1 + 9 i}{1 + i}

0.0036

m^{3} - 3 m + 2

35 (p^{2} - 1) = 24 p

What are the solutions to the equation 7x^2-2x-5=0 ?
The solutions to the equation 7x^2-2x-5=0 are x=1,x=-5/7
Find the zeros of 7x^2-2x-5=0
The zeros of 7x^2-2x-5=0 are x=1,x=-5/7