What are the solutions to the equation 148+2^2=x^2 ?

The solutions to the equation 148+2^2=x^2 are x=2sqrt(38),x=-2sqrt(38)

Find the zeros of 148+2^2=x^2

The zeros of 148+2^2=x^2 are x=2sqrt(38),x=-2sqrt(38)

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148 + 2^{2} = x^{2}

x = 238, x = - 238

Decimal Notation

x = 12.32882 \dots, x = - 12.32882 \dots

Solution steps

148 + 2^{2} = x^{2}

Switch sides

x^{2} = 148 + 2^{2}

Simplify

148 + 2^{2} : 152

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 152, x = - 152

152 = 238

- 152 = - 238

x = 238, x = - 238

5 - 3 t > - 7

4 x + 3 + 8 = 35

(- 4)^{- 1}

2 y^{2} - y - 6 > 0

\frac{1}{x} - 3 > 6

What are the solutions to the equation 148+2^2=x^2 ?
The solutions to the equation 148+2^2=x^2 are x=2sqrt(38),x=-2sqrt(38)
Find the zeros of 148+2^2=x^2
The zeros of 148+2^2=x^2 are x=2sqrt(38),x=-2sqrt(38)