What are the solutions to the equation x^2+11x=12 ?

The solutions to the equation x^2+11x=12 are x=1,x=-12

Find the zeros of x^2+11x=12

The zeros of x^2+11x=12 are x=1,x=-12

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x^{2} + 11 x = 12

x = 1, x = - 12

Solution steps

x^{2} + 11 x = 12

Move

12

to the left side

x^{2} + 11 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot (- 12) = 13

x_{1, 2} = \frac{- 11 \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 13}{2 \cdot 1}, x_{2} = \frac{- 11 - 13}{2 \cdot 1}

x = \frac{- 11 + 13}{2 \cdot 1} : 1

x = \frac{- 11 - 13}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 1, x = - 12

\frac{2}{3} (9 x - 6) - 4 = 9 x - 6

9 - x^{2} > 0

- 9 = 12 + 3 x

\frac{12 m - 6}{18 m - 9}

x^{2} - 2 x + 14 = 0

What are the solutions to the equation x^2+11x=12 ?
The solutions to the equation x^2+11x=12 are x=1,x=-12
Find the zeros of x^2+11x=12
The zeros of x^2+11x=12 are x=1,x=-12