What are the solutions to the equation 7x^2-7x-6=0 ?

The solutions to the equation 7x^2-7x-6=0 are x=(7+sqrt(217))/(14),x=(7-sqrt(217))/(14)

Find the zeros of 7x^2-7x-6=0

The zeros of 7x^2-7x-6=0 are x=(7+sqrt(217))/(14),x=(7-sqrt(217))/(14)

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7 x^{2} - 7 x - 6 = 0

x = \frac{7 + 217}{14}, x = \frac{7 - 217}{14}

Decimal Notation

x = 1.55220 \dots, x = - 0.55220 \dots

Solution steps

7 x^{2} - 7 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 7 ( - 6 )}{2 \cdot 7}

(- 7)^{2} - 4 \cdot 7 (- 6) = 217

x_{1, 2} = \frac{- ( - 7 ) \pm 217}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 217}{2 \cdot 7}, x_{2} = \frac{- ( - 7 ) - 217}{2 \cdot 7}

x = \frac{- ( - 7 ) + 217}{2 \cdot 7} : \frac{7 + 217}{14}

x = \frac{- ( - 7 ) - 217}{2 \cdot 7} : \frac{7 - 217}{14}

The solutions to the quadratic equation are:

x = \frac{7 + 217}{14}, x = \frac{7 - 217}{14}

3 x = \frac{2}{5}

(\frac{5}{3})^{0} 2^{- 1}

8 + 27 y^{3}

30 b + 53 \geq 18 b - 83

\frac{1}{2 \cdot 3}

What are the solutions to the equation 7x^2-7x-6=0 ?
The solutions to the equation 7x^2-7x-6=0 are x=(7+sqrt(217))/(14),x=(7-sqrt(217))/(14)
Find the zeros of 7x^2-7x-6=0
The zeros of 7x^2-7x-6=0 are x=(7+sqrt(217))/(14),x=(7-sqrt(217))/(14)