What is 3x-((2x)/3)<(1/2)+((3x)/4) ?

The solution to 3x-((2x)/3)<(1/2)+((3x)/4) is x< 6/19

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3x-((2x)/3)<(1/2)+((3x)/4)

3 x - (\frac{2 x}{3}) < (\frac{1}{2}) + (\frac{3 x}{4})

x < \frac{6}{19}

Interval Notation

(- \infty, \frac{6}{19})

Decimal Notation

x < 0.31578 \dots

Solution steps

3 x - (\frac{2 x}{3}) < (\frac{1}{2}) + (\frac{3 x}{4})

Move

(\frac{3 x}{4})

to the left side

\frac{19 x}{12} < \frac{1}{2}

Multiply both sides by

12

19 x < 6

Divide both sides by

19

x < \frac{6}{19}

1 + \frac{1}{2} (4 x - 6) = - 2

- 3 (x - 3) + 24 = 2 x - 5 (x - 9)

∣ m + 4 ∣ < - 2

r^{2} - 12 r + 40 = 0

2 y^{2} - 9 y - 5

What is 3x-((2x)/3)<(1/2)+((3x)/4) ?
The solution to 3x-((2x)/3)<(1/2)+((3x)/4) is x< 6/19