What are the solutions to the equation -6z^2-10z-3=0 ?

The solutions to the equation -6z^2-10z-3=0 are z=-(5+sqrt(7))/6 ,z=-(5-sqrt(7))/6

Find the zeros of -6z^2-10z-3=0

The zeros of -6z^2-10z-3=0 are z=-(5+sqrt(7))/6 ,z=-(5-sqrt(7))/6

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- 6 z^{2} - 10 z - 3 = 0

z = - \frac{5 + 7}{6}, z = - \frac{5 - 7}{6}

Decimal Notation

z = - 1.27429 \dots, z = - 0.39237 \dots

Solution steps

- 6 z^{2} - 10 z - 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 6 ) ( - 3 )}{2 ( - 6 )}

(- 10)^{2} - 4 (- 6) (- 3) = 27

z_{1, 2} = \frac{- ( - 10 ) \pm 2 7}{2 ( - 6 )}

Separate the solutions

z_{1} = \frac{- ( - 10 ) + 2 7}{2 ( - 6 )}, z_{2} = \frac{- ( - 10 ) - 2 7}{2 ( - 6 )}

z = \frac{- ( - 10 ) + 2 7}{2 ( - 6 )} : - \frac{5 + 7}{6}

z = \frac{- ( - 10 ) - 2 7}{2 ( - 6 )} : - \frac{5 - 7}{6}

The solutions to the quadratic equation are:

z = - \frac{5 + 7}{6}, z = - \frac{5 - 7}{6}

\frac{n ^{2}}{n ^{3}}

(\frac{4}{x})^{- 2}

\frac{a}{5} + 4 < 6

3 u^{2} - 84 = 0

(\frac{x ^{3} y ^{- 2}}{x y})^{- \frac{1}{5}}

What are the solutions to the equation -6z^2-10z-3=0 ?
The solutions to the equation -6z^2-10z-3=0 are z=-(5+sqrt(7))/6 ,z=-(5-sqrt(7))/6
Find the zeros of -6z^2-10z-3=0
The zeros of -6z^2-10z-3=0 are z=-(5+sqrt(7))/6 ,z=-(5-sqrt(7))/6